How do I randomly show 10/93 blocks, themselves divided unevenly into 7 bins, without replacement? | XM Community
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How do I randomly show 10/93 blocks, themselves divided unevenly into 7 bins, without replacement?

  • 3 September 2019
  • 1 reply
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Hello!



I am a PhD student in psychology runnning a study with some complicated randomization that I can't quite figure out how to implement in Qualtrics. I've described the math of what I need below, I'm just not sure how to make it happen in Qualtrics.



I have 93 blocks, divided _unevenly_ into 7 bins. Each block needs to be viewed by 50 participants, and each participant will see 10/93 blocks. The blocks need to be pulled from one of seven bins, in a quasi-random fashion. Specifically, because each bin has a different number of blocks in it (as you can see below) and I need each block to be seen 50 times across participants, blocks need to be randomly pulled from the bins at different probabilities. So, b/c of the # of blocks in each bin, out of the 10 blocks that each participant sees, on average 1.72 should be from Bin 1, 2.04 from Bin 2, etc. In other words, I need Qualtrics to randomly select each block (without repeats; e.g., I don't want a participant to see Block 17 more than once) from one of the bins based on those probabilities. So, for each block selected, there should be a 17.2% likelihood of it being from Bin 1, a 20.4% chance of it being from Bin 2, and so on for each block that is selected. Put differently, a block should be selected from Bin 1 17.2% of the time, but when a block is selected from Bin 1, it should be selected randomly and without replacement for a participant. Is this clear?



Is there a way to implement this in Qualtrics? I would really appreciate an answer to this as it's quite over my head.



Thank you!

A confused grad student



!
Probably possibly but not using native features.



If it were me, I'd probably connect with a consultant on here. I know @TomG consults.

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