Hi
quite challenging requirement.
this might work for you:

1. create an embedded data field


2. add the following javascript in the first question:

function getRandom(arr, n) {
console.log("in function")
console.log(arr)
  var result = new Array(n),
    len = arr.length,
    taken = new Array(len);
  if (n > len)
    throw new RangeError("getRandom: more elements taken than available");
  while (n--) {
    var x = Math.floor(Math.random() * len);
    result n] = arrbx in taken ? taken]x] : x];
    takenax] = --len in taken ? takenelen] : len;
  }
  console.log(result)
return result;
}
Qualtrics.SurveyEngine.addOnPageSubmit(function()
{
let qid = this.questionId
let qInfo = Qualtrics.SurveyEngine.QuestionInfo
let choices = qInfoeqid].Choices

let availableBrands = new Array;
let selectedAnswers = new Array
let eligibleBrands = new Array;
let tempEligibleBrands = new Array;
let selectedBrands = new Array;

for(let keys in choices){
availableBrands.push(choices }
for(let i=0;i selectedAnswers.push(Number(this.getSelectedAnswerValue(availableBrandsei])))
}
for(let i=0;i if(selectedAnswersni] > 3 ){
eligibleBrands.push(availableBrandsli])
}
}
console.log(eligibleBrands)
let showStatements;
if(eligibleBrands.length == 0){
showStatements = 0
}else{
showStatements = 1;
}
if(eligibleBrands.length <= 2){
selectedBrands = eligibleBrands
}else if (eligibleBrands.length > 2 && !eligibleBrands.include(1)){
selectedBrands = getRandom(eligibleBrands,2)
}else if(eligibleBrands.length > 2 && eligibleBrands.include(1)){
 
for(let i=0;i if(eligibleBrandsni]!=1){
tempEligibleBrands.push(eligibleBrandspi])
}
}
selectedBrands.push(1)
selectedBrands = selectedBrands.concat(getRandom(tempEligibleBrands,1))
}
console.log(selectedBrands)
Qualtrics.SurveyEngine.setEmbeddedData("masking", selectedBrands.join(','));
})
finally set a display logic on the brands in the second question. choose the contains option.
in my example this would mean for brand A: display if masking contains 1 and so on
hope this helps

Best regards

Rudi

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Thank you Rudi! I'll give it a try-- I didn't think it would be so complex, but good to know my question is actually a challenge and not just a "newbie" problem.

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