How to randomize blocks and match that order at a later point?

Aanurag_QC Thank you for your answer; too bad it cannot be programmed.

Okay, I figured out how to do this. My method is a bit messy - maybe someone who is a bit better at these things might be able to make it prettier. There are 3 steps...

1. Add embedded fields to your flow so that you are capturing the displayed order of the elements. This is basically what was described here; https://community.qualtrics.com/XMcommunity/discussion/comment/19934#Comment_19934

My implementation looks like this (screenshot 1):
2. Add javascript to your question block to capture the SurveyPath information and separate it into a list of new embedded variables (Disp1, Disp2) you will be able to put into use. One issue is that I needed to put a "buffer question" in to hold this code. This is a question that added between the Block Option 1, etc. and the later question (for part 3) where I will use the new embedded variables. Here is the code I used (screenshot 2) Note that I am not familiar with Java so this might be improved by someone - I have a lot of calls to the console so I can check my work.
Qualtrics.SurveyEngine.addOnload(function()
{
      var path = "${e://Field/SurveyPath}";
   console.log(path);
   myArray = path.split(",");
   var disp1=myArray[1];
   var disp2=myArray[2];
   console.log(disp1);
   console.log(disp2);
   Qualtrics.SurveyEngine.setEmbeddedData('Disp1', disp1);
      Qualtrics.SurveyEngine.setEmbeddedData('Disp2', disp2);
});

3. Then you need to actually use the new embedded variables in a question text. Here was my mock question (screenshot 3).
Hope this helps you and the next person looking to figure this out!

Oh, that should be fine as well. Do something like this for step 3 (you will still need the buffer question, I think). The idea is that you need to create a group with subbranches (you will need 6 subbranches because you have 6 blocks that might come first). The duplicate that group 5 more times, substituting Disp2 for Disp1, etc. etc. This follows their method, although I think my example is easier to follow....