How to randomly present one of two conditions based on answer to previous question?

Question

Hi! I'm not being able to solve this one out.
First I need to randomize participants at the beginning of the survey into 1 of 2 conditions. Lets call them Group 1 and 2.
Then, in each of these groups, I have an item which asks participants to select one of two options. Based on participants responses (lets say, participant chooses option 1), I need to send him randomly to either a condition "Option1_A or Option1_B" (if participant had chosen option 2, then I needed to send him randomly to either condition "Option2_A or Option2_B).

So that in the end I have 8 conditions.
2 (Group: 1 vs 2) x 2 (options 1 vs 2) x 2 (condition A vs B ).

Is there a way of doing this?

Thank you so much in advance!

fleb · Accepted Answer

Hi @filipe_loureiro,study following Qualtrics support: Survey flow, Embedded data, Randomizer,  and Branch logic. Then you'll be able to design such branching on your own. It's not hard.First branching: randomly assign a value of an embedded field for each participant and then branch according to the value of this embedded field.!!Second branching: this is fully described in the site about Branch logic.

filipe_loureiro · Answer

Hi @fleb,Thank you so much for your help and for the links!

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