Using keypresses for questions with choice randomization | XM Community
Skip to main content

Using keypresses for questions with choice randomization

  • November 8, 2022
  • 2 replies
  • 25 views
Q
Forum|alt.badge.img+3

Hello,

I currently have survey-takers pressing "E" to choose the left choice and "I" to choose the right choice. The question looks like this:
image.pngI want to keep it this way but randomize the choices. As is, "E" specifically triggers choice 1 and "I" choice 2.

Here is my current code:
let that = this;
Event.observe(document, 'keydown', function keydownCallback(e){

if (e.keyCode == 69) 
{
jQuery(this).trigger ("click");
that.setChoiceValueByRecodeValue(1,true);
that.clickNextButton();
}

if (e.keyCode == 73) 
{
jQuery(this).trigger ("click");
that.setChoiceValueByRecodeValue(2,true);
that.clickNextButton();
}
})
Is there any way I could get "1" and "2" to represent the left choice and the right choice?

I guess I might need to randomize the choices manually? Any ideas?

    2 replies

    TomG
    Level 8 ●●●●●●●●
    Forum|alt.badge.img+27
    • TomG
    • Level 8 ●●●●●●●●
    • November 8, 2022

    You can get the choice order like this:
    var choices = jQuery("#"+this.questionId+" [choiceid]");
    var leftChoice = choices.first().attr("choiceid");
    var rightChoice = choices.last().attr("choiceid");
    Then:
    ...
    if (e.keyCode == 69) 
    {
    jQuery(this).trigger ("click");
    that.setChoiceValue(leftChoice,true);
    that.clickNextButton();
    }
    ...

    Q
    Q
    Forum|alt.badge.img+3

    https://community.qualtrics.com/XMcommunity/discussion/comment/51922#Comment_51922This worked! I just had to change the variable name from choices for some reason. Thank you!


    Previous message:

    That seems like it would be perfect. For some reason it's not working.

    When I console log the 
    rightChoice
    and 
    leftChoice
    , I get undefined.


    Working from the beginning:

    When I console log choices, I get an object that I don't really understand. It looks like it's a length of 1 when it's set to a variable, different from the jQuery somehow.

    When I console log choices.first(), I get an object that I don' t understand. It looks like there are no elements/values, just keys.


    image.png

    Zoom in of the jQuery:

    image.png

    The query makes the left choice the zeroeth element, and the right choice the first element, so I could use that.

    For some reason choices[0] and choices[1] return undefined. However, indexing the query works. E.g.

    jQuery("#"+this.questionId+" [choiceid]")[0])
    Returns:


    The choice id is right there for the left option! I just need to reach it..

    TomG
    Terms & ConditionsAccessibility statement